6/(n^2-7n+12)=0

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Solution for 6/(n^2-7n+12)=0 equation: 


D( n )

n^2-(7*n)+12 = 0

n^2-(7*n)+12 = 0

n^2-(7*n)+12 = 0

n^2-7*n+12 = 0

n^2-7*n+12 = 0

DELTA = (-7)^2-(1*4*12)

DELTA = 1

DELTA > 0

n = (1^(1/2)+7)/(1*2) or n = (7-1^(1/2))/(1*2)

n = 4 or n = 3

n in (-oo:3) U (3:4) U (4:+oo)

6/(n^2-(7*n)+12) = 0

6/(n^2-7*n+12) = 0

n^2-7*n+12 = 0

n^2-7*n+12 = 0

DELTA = (-7)^2-(1*4*12)

DELTA = 1

DELTA > 0

n = (1^(1/2)+7)/(1*2) or n = (7-1^(1/2))/(1*2)

n = 4 or n = 3

(n-3)*(n-4) = 0

6/((n-3)*(n-4)) = 0

n belongs to the empty set

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